Performing regex Queries with pymongo

Just you want to try this one,  If you want to include regular expression options (such as ignore case)

import re
regx = re.compile("^foo", re.IGNORECASE)
db.users.find_one({"files": regx})

For the regex is changed pymongo is work done in different but is just as easy:

The following code as work like regex

db.collectionname.find({'files':{'$regex':'^File'}})

This following document will match like a document that have a files property that has a item within that starts with File

To ignore the duplicate compilation you can use the bson regex wrapper that comes with PyMongo

>>> regx = bson.regex.Regex('^foo')

>>> db.users.find_one({"files": regx})

The string is stored in the regex so find_one can then detect the argument as a ‘Regex’ type and form the appropriate Mongo query.

In Python answer should be a most valuable answer in other answer

>>> db.collectionname.find({'files':{'$regex':'^File'}})

if you plan to use regex queries because there are some caveats. It’s worth reading up on the bson Regex documentation